22=1/2(.6)(v)^2

Solution for 22=1/2(.6)(v)^2 equation:

22=1/2(.6)(v)^2

We move all terms to the left:

22-(1/2(.6)(v)^2)=0


Domain of the equation: 2(.6)v^2)!=0

v∈R


We add all the numbers together, and all the variables

-(1/2(0.6)v^2)+22=0

We multiply all the terms by the denominator


-(1+22*2(0.6)v^2)=0


We calculate terms in parentheses: -(1+22*2(0.6)v^2), so:

1+22*2(0.6)v^2

determiningTheFunctionDomain
22*2(0.6)v^2+1

Wy multiply elements

44v+1

Back to the equation:

-(44v+1)


We get rid of parentheses

-44v-1=0

We move all terms containing v to the left, all other terms to the right

-44v=1

v=1/-44

v=-1/44